Question 109897
{{{(x^3 *y^-4* z^0) / (5x^6 *y^8)^3}}}............{{{z^0 = 1}}} and {{{y^-4 = 1/y^4}}}

{{{(x^3 *1/y^4* 1) / (5x^6 *y^8)^3}}}........

Power Theorem for Exponents states {{{(x^m)^n = x^mn}}}

then 

{{{(x^3 /y^4) / (5^3*x^18 *y^24)}}}........



{{{x^3 /(y^4 *5^3x^18 *y^24)}}}........


{{{x^3 /(5^3x^18 *y^28)}}}........divide by {{{x^3}}} both nominator and denominator


{{{1 /(y^4 *5^3x^15 *y^24)}}}........