Question 1175204

Chelsea's distance traveled + Laura’s distance traveled = {{{138}}} miles

{{{t=6 }}}hours
{{{d=rt}}}

let Chelsea's rate be {{{r}}} and Laura’s rate be {{{r+5}}}

{{{6*r + 6*(r+5) = 138}}}
{{{6r + 6r+30 = 138}}}
{{{12r= 138-30}}}
{{{12r= 108}}}
{{{r= 108/12}}}
{{{r= 9}}}
=>Chelsea was  traveling {{{9(mil/h)}}}

then Laura’s rate was {{{r+5=9+5=14(mil/h)}}}