Question 1175153
If a line has an x-intercept at {{{x =-7}}} we have a point ({{{-7}}},{{{0}}})

 and a y-intercept at {{{y = -8}}}, we have a point ({{{0}}},{{{-8}}})

if you have two points you can find a slope:

{{{m=(y[2]-y[1])/(x[2]-x[1])}}}

{{{m=(-8-0)/(0-(-7))}}}

{{{m=-8/7}}}

so far its equation in the form {{{y = mx + b}}} is

{{{y = -(8/7)x + b}}}.... since y-intercept is {{{b}}}, {{{b=-8}}} 


and your equation is

{{{y = -(8/7)x -8}}}


{{{ graph( 600, 600, -10, 10, -10, 10, -(8/7)x -8) }}}