Question 109762
1.{{{2x + 3y = 1}}}
2.{{{5x + 3y = 16}}}
Multiply equation 2 by (-1) and add, 
{{{2x+3y-5x-3y=1-16}}}
{{{-3x=-15}}}
{{{highlight(x=5)}}}
From 1,
1.{{{2x+3y=1}}}
{{{2(5)+3y=1}}}
{{{10+3y=1}}}
{{{3y=-9}}}
{{{highlight(y=-3)}}}
There is a unique solution.
{{{ graph( 300, 300, -10, 10, -10, 10, 1/3-(2/3)x, 16/3-(5/3)x) }}}