Question 1174964
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Answer:  2/9


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Work Shown:


The given table is
<table border = "1" cellpadding = "5"><tr><td>x</td><td>1</td><td>2</td><td>3</td><td>4</td><td>5</td><td>6</td></tr><tr><td>y</td><td>20</td><td>5</td><td>3</td><td>2</td><td>4</td><td>2</td></tr></table>
x = number of donations made
y = number of students


We have 2+4+2 = 8 students who made more than 3 donations. We find this by adding the values of y that correspond to x = 4, x = 5, x = 6; all of these x values are greater than 3 (to indicate more than 3 donations were made).


There are 20+5+3+2+4+2 = 36 students total.


The probability of getting a student who made more than three donations is therefore: 
8/36 = (4*2)/(4*9) = 2/9 

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