Question 1174949
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"Solve for x in terms of y and a" means that your teacher wants you to get x all by itself, and have some expression with y's and/or a's on the other side.


Currently we have x on the right side and it's buried in a somewhat complicated fraction.


What we can do is multiply both sides by (2a-x) to move that term over. Then we apply distribution.


y = (a-x)/(2a-x)
y(2a-x) = a-x
y*2a+y(-x) = a-x
2ay - xy = a-x


After doing those steps, let's get all of the terms that have 'x' in them to one side. Everything else gets to the other side.


2ay - xy = a-x
2ay - xy+x = a-x+x
2ay - xy+x = a
2ay - xy+x-2ay = a-2ay
-xy+x = a-2ay
x-xy = a-2ay


Note how we can factor out x from the left side. We're using the distributive property. After factoring, divide both sides by (1-y) to fully isolate x


x-xy = a-2ay
x(1-y) = a-2ay
<font color=red>x = (a-2ay)/(1-y)</font>


We've reached our goal of getting x all by itself on one side. The other side consists of some combination of 'a's and 'y's in which we are applying arithmetic operations to them. 
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