Question 1174871
<br>
{{{sin(x)^2+cos(x)^2=1}}}<br>
Given sin(x)=k, use that to find an expression for cos(x).
{{{cos(x)^2 = 1-sin(x)^2}}}
{{{cos(x) = sqrt(1-sin(x)^2)}}}<br>
Plug in the given expression for sin(x).<br>
Cosine is negative in quadrant II, so write the expression as a negative value.<br>
Then<br>
{{{tan(x) = sin(x)/cos(x)}}}<br>