Question 1174786
<pre>
The trick for reversing a subtraction A-B to make it involve B-A is to
multiply by -1, making it -A+B, then you can turn it around as B-A.

{{{(3x^3)/(3x-6^"")}}}{{{""=""}}}{{{(3x^3)/(3(x-2)^"")}}}{{{""=""}}}{{{(cross(3)x^3)/(cross(3)(x-2)^"")}}}{{{""=""}}}{{{(x^3)/(x-2^"")}}}{{{""=""}}}{{{x^3/(x-2^"")}}}{{{""*""}}}{{{((-1^"")(x^2+9))/((-1^"")(x^2+9))}}}{{{""=""}}}
{{{((-x^3)(x^2+9))/((-x+2^"")(x^2+9))}}}{{{""=""}}}{{{(-x^5-9x^3)/((2-x^"")(x^2+9))}}}

Edwin</pre>