Question 1174719
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Hi

(2^x+1)/(2^x-1)=5
(2^x+1) = 5(2^x-1) = 5(2^x) - 5

(2^x+1) = 5(2^x) - 5
   6 = 3(2^x)
{{{log(2, 2)}}}= x = 1

Wish You the Best in your Studies.
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