Question 1174647

Your Answer:
Rex had altogether 212 $1 & $5 notes.
let a = no. of $1 notes
let b = no. of $5 notes
therefore
a + b = 212
or
a = (212-b), use this form for substitution
:
 After using 1/3 of the $1 notes, he took out another 12 $5 notes from his cash box.
Now {{{2/3}}}a = $1 notes remain in the cash box
and
(b-12) = $5 notes remain in the cash box
:
 Now the number of 5 dollar notes he has is 1/4 the number of 1 dollar notes remaining.
b - 12 = {{{1/4}}}*{{{2/3}}}a
b - 12 = {{{2/12}}}a
reduce fraction
b - 12 = {{{1/6}}}a
multiply both sides by 6
6(b-12) = a
6b - 72 = a
replace a with (212-b)
6b - 72 = 212 - b
6b + b = 212 + 72
7b = 284
b = 284/7
b = 40.157
These kind of problems have to have integer solutions, something is wrong with this problem!!
:
 How many 5 dollar notes did he have at first.