Question 1174657
{{{-2x+y=6}}}.....eq.1 
{{{y=x-8}}}......eq.2
--------------------------substitute {{{y}}} from eq.2 in eq.1


{{{-2x+x-8=6}}}.....eq.1 ...solve for {{{x}}}

{{{-x-8=6}}}

{{{-6-8=x}}}


{{{x=-14}}}

go to

{{{y=x-8}}}......eq.2, substitute {{{x}}}

{{{y=-14-8}}}

{{{y=-22}}}