Question 1174619
Given the graph of the function {{{y=x^3-3x^2-6x+8}}}:

{{{ graph( 600, 600, -10, 10, -10, 10, x^3-3x^2-6x+8) }}}


from the graph we can see that {{{-2}}} ,{{{1}}} and  {{{4}}}  are zeros

 
{{{drawing( 600, 600, -10, 10, -10, 10, 
circle(-2,0,.14),circle(1,0,.14),circle(4,0,.14),
 graph( 600, 600, -10, 10, -10, 10, x^3-3x^2-6x+8)) }}}

so, answer is

Zeros: {{{x}}}= {{{-2}}},{{{1}}},and {{{4}}}.