Question 1174588
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Notice that  2 + 2i = {{{2*sqrt(2)*(sqrt(2)/2 + i*(sqrt(2)/2))}}} = {{{2*sqrt(2)*cis(pi/4)}}}.


Therefore, according to deMoivre's formula


    {{{(2 + 2i)^6}}} = {{{(2*sqrt(2))^6*cis(6pi/4)}}} = {{{2^9*cis(3pi/2)}}} = -512*i.     <U>ANSWER</U>
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