Question 1174584
Cot𝈚=-2/9.
Recall that cot𝈚=1/tan𝈚
1/tan𝈚=-2/9. 
Cross multiplying,we have
9x1=-2tan𝈚
9=-2tan𝈚
9/-2=tan𝈚
-4.5=tan𝈚
tan𝈚=-4.5
𝈚=arctan(4.5)
𝈚=77.45
𝈚 approx. 77.5(1dp)
cos𝈚 > 0. 
Cos77. 5 > 0. 
O.216 > 0.True