Question 1174560
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If the equations are to be of the same line, then the two equations in Px+Qy=C should both have the same constant C.<br>
So multiply the first equation by 10/7.  Then we have<br>
{{{(20/7)x-(10B/7)y = 10}}}
{{{Ax+3y = 10}}}<br>
Now, since these equations are the same,<br>
{{{A = 20/7}}}<br>
and<br>
{{{-10B/7 = 3}}}
{{{-10B = 21}}}
{{{B = -21/10}}}<br>
ANSWERS: A = 20/7; B = -21/10<br>