Question 1174562
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            The solution by  @ewatrrr to the last question is  ABSOLUTELY  WRONG.


            Below see my correct solution.



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Let the letters mean

    P - passenger car
    T - truck
    S - SUV
    C - crossover
    M - Minivan.


Then the probability under the last question is the sum of  {{{C[5]^3}}} = 10 addends

    p = p(PTS) + p(PTC) + p(PTM) + p(TSC) + p(TSM) + p(SCM) + . . . 


where all combinations of 5 letters taken 3 at a time are used.


Each p(XYZ) is the product of the 3 (three) relevant given probabilities.


So, according to the problem's instruction, I do not calculate, but only EXPLAIN how to build the calculation formula.
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