Question 1174562
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Hi
Passenger Car 0.46 - Pickup Truck 0.15 - SUV 0.10 - Crossover .24 - Minivan 0.05

P(crossover) = 1 - .46 -.15 - .10 - .05 = .24
P(pickup|Not car) = .15/.54
P(pickup truck, SU, or minivan) = .15 + .10 + .05

Select 3: the probability that the vehicles are of three different types
Yes,  5C3 0r 10 ways of selecting a trio from 5 types.
&
P(of each trio)... would be the product of their individual probabilities
Total Probability(vehicles are of three different types) would be the sum of
each of the possible trios. 

Wish You the Best in your Studies.
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