Question 1174548
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{{{4(cos(30) + i sin(30)) / 5(cos(70) + i sin(70)) = (4*cis(30))/(5*cis(70)) = (4e^(30i))/(5e^(70i)) = (4/5)e^(-40i) = (4/5)*(cis(-40)) = (4/5)cos(-40)+(4/5)i*sin(-40)}}}<br>