Question 109751
{{{L^2-16L+60=0}}} Start with the given expression


{{{(L-10)(L-6)=0}}} Factor the left side (note: if you need help with factoring, check out this <a href=http://www.algebra.com/algebra/homework/playground/change-this-name4450.solver>solver</a>)




Now set each factor equal to zero:


{{{L-10=0}}} or {{{L-6=0}}}


{{{L=10}}} or {{{L=6}}}  Now solve for L in each case



So our solutions are {{{L=10}}} or {{{L=6}}}



Notice if we graph {{{y=L^2-16L+60}}} we get


{{{ graph(500,500,-8,12,-8,12, x^2-16x+60) }}}


and we can see that the graph has roots at {{{L=10}}} and {{{L=6}}}, so this verifies our answer.