Question 1174417
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Formally....<br>
x = cost of each child ticket
y = cost of each adult ticket<br>
9x+8y = 145  (1st day total sales)
2x+8y = 82  (2nd day total sales)<br>
Solve by subtracting the second equation from the first, giving
7x = 63<br>
Use that to find the cost of each adult ticket, x; then use that value with the total sales for either day to find the cost of each child ticket.<br>
That's a simple example of an algebraic solution.  You can get the answer informally by doing exactly the same calculations without the formal algebra.<br>
9 adult tickets and 8 child tickets for $145, and 2 adult tickets and 8 child tickets for $82, means 9-2=7 adult tickets cost $145-$82 = $63.
7 adult tickets for $63 means $63/7 = $9 for each one.
2 adult tickets and $9 each, for a total of $18, plus 8 child tickets for a total of $82, means 8 child tickets for $82-$18 = $64
8 child tickets for $64 means $64/8 = $8 for each one.<br>