Question 1174367
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There are many different kinds of problems where the basic task is to solve a system that says the sum of two numbers is A and the difference of the two numbers is B.<br>
If a formal algebraic solution is required, then something like what the other tutor showed is fine.<br>
But if the speed of solving the problem is important and a formal algebraic solution is not required (as in a timed math competition), there is a quick and easy informal way to solve this type of problem.<br>
Look at it this way:
There is a number somewhere on a number line.
If you add some number, you reach A; if you subtract the same number, you reach B.
You went equal distances in opposite directions from the starting point to reach A and B; that means the starting point is halfway between A and B.  Mathematically, that means the starting point is the average of A and B.<br>
So one of the two numbers you are looking for is the average of the sum and difference of the two numbers; then the second number is the difference between that average and either of the numbers.<br>
That's a lot of words of explanation - but using the process is simple.<br>
For this example, we have a difference of 7 and a sum of 17.
One of the numbers is the average of 7 and 17, which is (7+17)/2 = 12.
The other number is the difference between 7 and 12, or between 12 and 17, which is 5.<br>
ANSWER: 12 and 5<br>
A couple of other quick examples to see how easy this method is....<br>
Sum 24 and difference 6 --> first number (24+6)/2 = 30/2 = 15; second number 24-15=9, or 15-6=9<br>
Sum 37 and difference 29 --> first number (37+29)/2 = 33; second number 37-33=4, or 33-29=4<br>