Question 1174347
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This might be overkill, but think of x as (x)


So we're dealing with y = 2(x)^2 + 1


Replace every copy of x with -2 and evaluate to get


y = 2(x)^2 + 1
y = 2(-2)^2 + 1
y = 2(-2)*(-2) + 1
y = 2(4) + 1
y = 8 + 1
<font color=red>y = 9</font>


I have a feeling your steps probably looked like this
y = 2x^2 + 1
y = 2(-2)^2 + 1
y = 2(-4) + 1
y = -8 + 1
y = -7
Which is not correct because (-2)^2 is equal to positive 4, and not negative 4.
Think of (-2)^2 as (-2)*(-2) = 4. The two negatives multiply to a positive.
In short, we're squaring all of the value and that includes the negative.


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Answer:  <font color=red>y = 9</font>
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