Question 1174304
when y varies directly with the square of a and inversely with the square root of b.
{{{y = (ka^2)/(sqrt(b))}}} 
If y=6 when a=4 and b=16
find k
{{{(4^2k)/sqrt(16)}}} = 6 
{{{(16k)/4}}} = 6
mult by 4
16k = 4*6
k = 24/16
k = 1.5
:
find y when a=8 and b=4?
y = {{{1.5(8^2)/sqrt(4)}}}
y = {{{1.5(64)/sqrt(4)}}}
y = {{{96/2}}}
y = 48
:
Sorry about this unforgivable error!