Question 1174289
Earl solved the following system of equation using substitution.
x + y = 3 
2x - 3y = 16 

Earl's Solution 
2(3-y)-=16
6-y-3y=16

6-4y=16
6-6-4y=16-6
    4y=10
   -4y=10 
   -4= -4
y=-2.5
x+(-2.5)=3
x=5.5

Unfortunately, he made a mistake. Locate his error
<pre>Those 2 are both WRONG!!
The error is NOT with the "- 3y".
The "-" is there on Line 1, but the "3y" is missing. However, the "- 3y" was included on Line 2. 
So, it was left out of one of the lines but wasn't forgotten, and was certainly included in the solution!

2(3-y)-=16 <==== Line 1
6-y-3y=16 <===== Line 2
6-4y=16 <======= Line 3
As seen above, the error was made in Line 2 as he DISTRIBUTED the 2 to the (3 - y), but got 6 - y instead of 6 - 2y. That's where the TRUE error lies!
That's all thatw's asked - to find the ERROR! Nothing else!!