Question 1174242
Solve 2r-³=- 16 
<pre>Answer depends on whether this is: {{{system(highlight(matrix(1,3, 2r^(- 3), "=", - 16)), or, highlight(matrix(1,3, 2r^3, "=", - 16)))}}}
If <b><u>FORMER</b></u>, then it's {{{- 1/2}}}, but if the <b><u>LATTER</b></u>, it's - 2.