Question 1174264
<br>
The diameter of the outer semicircle is 10m, and the segments between the two semicircles are each 0.5m long, so the diameter of the inner semicircle is 9m.<br>
outer semicircle diameter 10m --> arc length 5pi meters
inner semicircle diameter 9m --> arc length 4.5pi meters
20 segments each 0.5m long --> 10m<br>
ANSWER: Total length of iron required: (10+9.5pi) meters<br>