Question 1174240
<font face="Times New Roman" size="+2">


Let *[tex \Large x] represent the amount of items manufactured and then make the utterly ludicrous assumption that every item manufactured was sold for price *[tex \Large p]


Cost function:  *[tex \Large C(x)\ =\ 30x\ +\ 1200]


Revenue function:  *[tex \Large px]


Profit function:  *[tex \Large P(x)\ =\ R(x)\ -\ C(x)\ =\ px\ -\ (30x\ +\ 1200)]


"break even" [sic] means *[tex \Large P(x)\ =\ 0].  We are given that break-even occurs when the number of sales is 60.


Hence:  *[tex \Large P(60)\ =\ 0].  Solve *[tex \Large P(60)] for *[tex \Large p]


																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
*[illustration darwinfish.jpg]

From <https://www.algebra.com/cgi-bin/upload-illustration.mpl> 
I > Ø
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}
</font>