Question 1174215
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Note that the calculations are straightforward (although a bit ugly) once you have set up the problem; by far the most important part of solving the problem is converting the given information into an appropriate equation.<br>
So pay close attention to that part of the solution below.<br>
The total investment is $10,000; let x be the amount invested at 8.5% and ($10,000-x) be the amount invested at 6.75%.  Note that is a typical strategy for starting on a problem where the sum of two numbers is given -- one number is x, and the other is the given sum minus x.<br>
The interest from the first investment is 8.5% of x; the interest from the second is 6.75% of ($10,000-x).<br>
The  interest from the first investment was $14 more than twice the interest from the second:<br>
{{{0.085(x) = 2(0.0675(10000-x))+14}}}<br>
Solve algebraically; or graph the two expressions on a graphing calculator and see that they intersect at x=6200.<br>
So $6200 was invested at 8.5%, and the other $3800 was invested at 6.75%.<br>
To check that....<br>
.085(6200) = 527
.0675(3800) = 256.50
2(256.50)+14 = 513+14 = 527<br>