<PRE><B>Question 1174149</B>
.


&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;The solution by @ewatrrr looks frighteningly.


&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;It is because she selected &amp;nbsp;IMPROPER &amp;nbsp;way to solve the problem.


&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;Actually, &amp;nbsp;there is &amp;nbsp;MUCH &amp;nbsp;SIMPLER &amp;nbsp;way, &amp;nbsp;pointed by @greenestamps.


&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;I decided to complete the solution in that way to convince you &amp;nbsp;HOW &amp;nbsp;SIMPLE &amp;nbsp;it is.



&lt;pre&gt;
The two lines are


    y = {{{(-2/7)x}}} + 7

    y = {{{(7/2)x}}}.


Their intersection is


    {{{(-2/7)x + 7}}} = {{{(7/2)x}}}.


Multiply both sides by 14 to get


    -4x + 98 = 49x

          98 = 49x + 4x = 53x

           x            = {{{98/53}}}.


You may consider the segment  [0,7]  along the y-axis as the base of our right-angled triangle.


Thus the base has the length of 7 units, while the altitude of the triangle, drawn to this base is  {{{98/53}}}  units long.


Hence, the area of the triangle is  {{{(1/2)*7*(98/53)}}} = {{{686/106}}} = 6.472  square units  (rounded).    &lt;U&gt;ANSWER&lt;/U&gt;
&lt;/pre&gt;

Solved.


May the Lord saves you from solving the problem in a way how &amp;nbsp;@ewatrrr does it . . . 


Let her post be a lesson for you on how this problem &amp;nbsp;SHOULD &amp;nbsp;NOT &amp;nbsp;be solved.



</PRE>