Question 109700
Start with the given distance formula

{{{d=sqrt((x[1]-x[2])^2+(y[1]-y[2])^2)}}} where *[Tex \Large \left(x_{1}, y_{1}\right)] is the first point *[Tex \Large \left(6,2\right)] and *[Tex \Large \left(x_{2}, y_{2}\right)] is the second point *[Tex \Large \left(0,-3\right)]


{{{d=sqrt((6-0)^2+(2--3)^2)}}} Plug in {{{x[1]=6}}}, {{{x[2]=0}}}, {{{y[1]=2}}}, {{{y[2]=-3}}}


{{{d=sqrt((6)^2+(5)^2)}}} Evaluate {{{6-0}}} to get 6. Evaluate {{{2--3}}} to get 5. 


{{{d=sqrt(36+25)}}} Square each value


{{{d=sqrt(61)}}} Add


So the distance approximates to


{{{d=7.81024967590665}}}


which rounds to

7.81


So the distance between (6,2) and (0,-3) is approximately 7.81 units