Question 1174149
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Hi,
Find the area of a triangle bounded by the y-axis, the line f(x) = 7− (2)/(7)x
 y = -(2/7)x + 7
and the line perpendicular to f(x) that passes through the origin...
  y = (7/2)x
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    7 − (2/7)x = (7/2)x
    7 = (4 + 49)/14)x = (x)53/14
    (14/53)7 = x = 1.849  and y = 6.47   {{{(7/2)(1.849)}}}
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    D = {{{ sqrt ( (x[1]-x[2])^2+ (y[1]-y[2])^2 ) }}} 
    P(1.849, 6.47) &  P(0,0)    and      P(1.849, 6.47)  & P(0,7)

  Area = (1/2)bh = {{{(1/2)(sqrt((1.849)^2 + (6.47)^2))*(sqrt((1.849)^2 +  (7 - 6.47)^2))}}}

{{{drawing(300,300,    -10,10,-10,10, 
 grid(1),
circle(0, 7,0.4),
circle(1.85,6.47,0.4),
graph( 300, 300, -10,10,-10,10,0, (-2/7)x + 7 , (7/2)x) )}}}

Will leave it to You to finish up.  Important You are comfortable with Your calculator.

Wish You the Best in your Studies.
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