Question 1174089
2B is a Poisson distribution with lambda= to the number of characters in your first name. P(x< =3) would be poissoncdf(char.,2)ENTER. The "2" is the largest number of accidents below 3 and includes 0 and 1 but not 3.
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p(0-5) is 0.3872, so 1-that probability is the answer or 0.6128
p(Media Dept ) is 1/6 so probability none is from median dept is (5/6)^12=0.1122
this is p (0,1,2,3):p(0) is (2/3)^12=0.0078; p(1) is 12*(2/3)^11*(1/3)=0.0424; 66*(2/3)^10*(1/9)=0.1272, the 66 coming from 12C2; and p(3)=220*(2/3)^9*(1/27)=0.2120
total is 0.3931. Also from binomialcdf(12, (1/3),3) ENTER.