Question 1174098
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The polar form of the complex number *[tex \Large a\ +\ bi] is *[tex \Large (r,\theta)] where *[tex \Large r\ =\ \sqrt{a^2\,+\,b^2}] and *[tex \Large \theta =\ \arctan\(\frac{b}{a}\)].  You can do your own arithmetic.  


																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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From <https://www.algebra.com/cgi-bin/upload-illustration.mpl> 
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