Question 1173931
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If a formal algebraic solution is not required, here is a quick and easy way to solve two-part "mixture" problems like this.<br>
All $8000 borrowed at 14% would incur $1120 interest.
All $8000 borrowed at 5% would incur $400 interest.
The actual interest was $8850-$8000 = $850.<br>
Look at the three interest amounts $400, $850, and $1120 on a number line and calculate that $850 is $450/$720 = 5/8 of the way from $400 to $1120.<br>
That means 5/8 of the money was borrowed at the higher rate.<br>
ANSWER: 5/8 of the $8000, or $5000, was borrowed from the bank at 14% interest; the other $3000 was borrowed from her uncle at 5% interest.<br>
CHECK: .14(5000)+.05(3000) = 700+150 = 850<br>