Question 109655

let {{{x}}} be {{{1st}}} consecutive even integer
{{{y=x+2}}} be {{{2nd}}} consecutive even interger
{{{z=x+4}}} be {{{3rd}}} consecutive even integer

then:

{{{x + y + z <= 126}}}

{{{x+(x+2)+(x+4)<=126}}}

{{{3x + 6 <= 126}}}........move {{{6}}} to the right

{{{3x <= 126 - 6}}}

{{{3x <= 120}}}.....divide both sides by {{{3}}}

{{{x <= 40}}}........ {{{1st}}} consecutive even integer

{{{y = 42}}}.......{{{2nd}}} consecutive even interger

{{{z = 44}}}.........{{{2nd}}} consecutive even interger