Question 1173983
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For such a polynomial, the roots are  2, -3, -3i  and  3i, including all complex conjugates,


so the polynomial is  


     p(x) = (x-2)*(x-(-3))*(x-(-3i))*(x-3i) = (x-2)*(x+3)*(x^2 + 9).
</pre>

Solved, answered and explained.