Question 1173909
index 2 is square root; index 3 is cube root
I will write as fractional exponents
24^(1/3)/125^(1/3)
the denominator is 5
the numerator is 8^(1/3)*3^(1/3) or 2*3^(1/3)
=(2/5)*3^(1/3)
I can't follow what you did to get 120/125. Cube root of 120 is 8^(1/3)*15^(1/3)=2*15^(1/3)
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cube root of (2/3)=2^(1/3)/3^(1/3)
multiply top and bottom by 3^(2/3), which makes the denominator 3.
numerator is 2^(1/3)*3^(2/3) and can also write as 6^(1/3)*3^(1/3)=18^(1/3)
18^(1/3)/3. Don't cancel.