Question 1173883
{{{n+8(1/n)=-6}}}

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{{{n^2+8=-6n}}}

{{{n^2+6n+8=0}}}

{{{(n+2)(n+4)=0}}}

{{{system(highlight(n=-2),or,highlight(n=-4))}}}



check:
{{{-2-8/2=-2-4=-6}}}
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{{{-4-8/4=-4-2=-6}}}


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Problem should be written,  The sum of a number and eight times its reciprocal is  negative 6.