Question 109622
Solve the equation:

{{{p=sqrt(2p-1)}}}........raise both sides to second power

{{{p^2 = (sqrt(2p - 1))^2}}}

{{{p^2 = 2p - 1}}}
or, move both terms from right side to the left side

{{{p^2 - 2p + 1 = 0}}}

{{{(p-1)^2=0}}}

then
{{{p-1=0}}}

{{{p = 1}}}

Solve the equation:sqrt 

{{{k+2=2}}}

{{{k = 2 - 2}}}

{{{k = 0}}}

Solve the equation:

{{{sqrt(2a)=2}}}........raise both sides to second power

{{{(sqrt(2a))^2 = 2^2}}}

{{{2a = 4}}}....divide both sides by {{{2}}}

{{{a = 2}}}


Solve the equation:

{{{sqrt(z)=-1}}}.....raise both sides to second power

{{{(sqrt(z))^2=(-1)^2}}}.....

{{{z = 1}}}