Question 1173642
First let's say that x is the number of lines of code, h=cost of the in house programming development, and s=cost of software developed outside the firm.

a) Here we want to figure out when h=s
   h=35000+1.5x (formula for annual inhouse cost)
   s=2.5x  (formula for annual outside cost)
   If h=s then 35000+1.5x=2.5x (subtract 1.5x from each side to get variable on one side)
                        x=35000
   Therefore 35000 lines of code need to be made per year to make the costs equal.

b) We will input 35000 instead of x because it is the number of lines of code
   h=35000+1.5*35000
    =$87500           
It was already established that with 35000 lines of code both costs will be equal but we will find the value for "s" just to check if our answer for a was correct.
   s=2.5*35000
    =$87500 (they are both the same)
   Therefore the costs of both options is $87500

c) Since the options are already equally costly the inhouse cost per line would be the same as it already is which would be $1.5