Question 1173653
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<pre>

The number of all possible triples of balls (independently of their colors) is

    {{{C[8]^3}}} = {{{(8*7*6)/(1*2*3)}}} = 56.



The number of favorable triples is

    {{{C[3]^2}}}.{{{C[2]^1}}} = 3*2 = 6.


THEREFORE, the probability under the problem's question is  P = {{{6/56}}} = {{{3/28}}}.       <U>ANSWER</U>
</pre>

Solved.


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