Question 1173541
<pre>
x-3y+z = 2
3x-4y+z = 0
4x+2y-z = 1

The matrix equivalent is:

{{{ (matrix(3,3, 1, -3, 1, 3, -4, 1, 4, 2, -1))*(matrix(3,1, x, y,z)) }}} = {{{ (matrix(3,1, 2, 0 , 1)) }}}

and the solution is
{{{ (matrix(3,1, x, y,z)) }}} = {{{ (matrix(3,3, 2/3, -1/3, 1/3, 7/3, -5/3, 2/3, 22/3, -14/3, 5/3))*(matrix(3,1, 2, 0, 1)) }}}

{{{ (matrix(3,1, x, y,z)) }}} = {{{ (matrix(3,1, 4/3+0+1/3, 14/3+0+2/3, 44/3+0+5/3)) }}}

{{{ (matrix(3,1, x, y,z)) }}} = {{{ (matrix(3,1, 5/3, 16/3, 49/3)) }}}