Question 109600
{{{S=(pi)*r*sqrt(r^2+h^2)}}} Original equation.
{{{S^2=(pi)^2*r^2*(r^2+h^2)}}}Square both sides. 
{{{S^2=(pi)^2*r^4+(pi)^2*r^2*(h^2)}}}Distributive property.
{{{S^2-(pi)^2*r^4=(pi)^2*r^2*(h^2)}}}Move non-h terms to one side. 
{{{(S^2-(pi)^2*r^4)/((pi)^2*r^2)=h^2}}}Divide by h coefficient. 
{{{h=sqrt(S^2-(pi)^2*r^4)/((pi)*r)}}}Square root of both sides.