Question 1173525
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How many ways are there for 5 men and seven women to stand in a line so that three {{{highlight(particular)}}} women
stand next to each other
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<pre>
From the remote point of view, you consider these 3 women as one clued object.


So the total number of object to permute, from this point of view is  5 + 7 - 2 = 10.


For 10 objects, you have  10! = 10*9*8*7*6*5*4*3*2*1 = 3628800 permutations.


Now, from the close point of view, there are 3! = 3*2*1 = 6 possible permutations inside this group of the 3 women.


It gives the total  6*3628800 = 10886400  possible permutationns.    <U>ANSWER</U>
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Solved.