Question 109587


In an equilateral triangle, all sides are of equal length.

one side is {{{10ab - 2a}}}, and another side is {{{a}}}

=> {{{10ab - 2a = a}}} ....on left side common factor is {{{2a}}}, factor it out

=> {{{2a(5b - 1) = 1}}}.........cancel {{{a}}} 

=> {{{2(5b - 1) = 1}}}.........

=> {{{10b - 2  = 1}}}.........

=> {{{10b  = 1 + 2}}}.........

=> {{{10b = 3}}}.........divide both sides by {{{10}}}

=> {{{b = 3/10}}}

check:

{{{10ab - 2a = a}}} 

{{{10*a*(3/10) - 2a = a}}}......cancel both {{{10}}}


{{{3a - 2a = a}}}......

{{{a = a}}}......