Question 1173460
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Hi
{{{drawing(400,400,-2.5,2.5,-2.5,2.5, 
locate(-2.1,-1,B), locate(-2,1.2,A), locate(2,1.1,D), locate(2,-1,C),
 green(line(2,1,2,1),line(-2,1,2,-1)),
line(-2,1,-2,-1), line(-2,-1,2,-1), line(2,-1,2,1), line(2,1,-2,1) )}}}
a rectangle has a diagonal of 5in and a length of 4in.
Pythagorean Theorem:  a^2 + b^2 = c^2
Let x be the width
4^2 + x^2 = 5^2   |Diagonal being 5"
x^2 = 25-16
x^2 = 9in^2
x = ± 3
Width = 3in   |Tossing out the Negative Solution of -3  for Length
Wish You the Best in your Studies.