Question 1173416
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You are given two sides of the triangle a= 85 m  and  b= 102 m,

and the third side  c= 127 m opposite to the angle under consideration.


You need to find the angle {{{gamma}}}  between the sides  "a"  and  "b".


Use the Cosine law 


    c^2 = {{{a^2 + b^2 - 2bc*cos(gamma)}}}.


From this formula,  find  


    {{{cos(gamma)}}} = {{{(c^2 - a^2 - b^2)/(2bc)}}} = {{{(127^2 - 85^2 - 102^2)/(2*85*102)}}} = -0.08651.


Then  {{{cos(gamma)}}} = arccos(-0.08651) = 1.6574 radians = 95 degrees (approximately).


<U>ANSWER</U>.  The angle is about 95 degrees.
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Solved.