Question 109561
(x-2)/( x^2-2x-15)  - (x+2) / (x^2-x-20)

=(x-2)/[(x-5)(x+3)] - (x+2)/[(x-5)(x+4)]

LCD = (x-5)(x+3)(x+4)

= [(x-2)(x+4)/LCD] - [(x+2)(x+3)/LCD]

= [x^2+2x-8 -(x^2+5x+6)]/LCD

= [-3x-14]/LCD

= -(3x+14)/[(x-5)(x+3)(x+4)]

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Cheers,
Stan H.