Question 1173372
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Hi
{{{x^(3a) * x^b = x^(3a+b)}}}   x^3a * x^b = x^3(a+b)
Problem 2
(-3ax^2)^0 = 1  {{{a^0 = 1}}}
Problem 3
4ab(6a^2b^3) divided by -16a^3b^3 = {{{(-3b/2)}}}
Problem 4
56^0(x^3) = x^3    56^0 = 1    {{{a^0 = 1}}}
Problem 5 
(-4xy^2)^2 divided by 16x^4y^5 = 1/(x^2y)
Parenthesis for clarity when needed
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