Question 1173367
Can start with the point (-5, 1) in the second quadrant then go to the right 3 and up 2 or go to the left 3 and down 2.
the line's equation using point slope formula y-y1=m(x-x1) m slope, (x1, y1) point
y-1=(2/3)(x+5)
y=(2/3)x+13/3
{{{graph(300,300,-10,10,-10,10,(2/3)x+13/3)}}}